Re: cases

#51940
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    `\begin{equation}
    \Pi_{rad}(\omega)=\frac{\omega^2\rho_0}{4\pi c_0}
    \begin{cases}\displaystyle
    \displaystyle\int_S{\int_S{v^*(\omega,Q)\frac{\sin(k|P-Q|)}{k|P-Q|}v(\omega,Q)\,dS}\,dS}, &\text{ se } P\neq Q \\[2ex]
    \displaystyle\int_S{\int_S{v^*(\omega,Q)v(\omega,Q)\,dS}\,dS}, &\text{ se } P\equiv Q
    \end{cases}
    \label{eq:rad_ac_powr_final}
    \end{equation}`
    Prova così.

    Ciao,
    ansys.

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