2 Novembre 2010 alle 17:50
#51940
::
`\begin{equation}
\Pi_{rad}(\omega)=\frac{\omega^2\rho_0}{4\pi c_0}
\begin{cases}\displaystyle
\displaystyle\int_S{\int_S{v^*(\omega,Q)\frac{\sin(k|P-Q|)}{k|P-Q|}v(\omega,Q)\,dS}\,dS}, &\text{ se } P\neq Q \\[2ex]
\displaystyle\int_S{\int_S{v^*(\omega,Q)v(\omega,Q)\,dS}\,dS}, &\text{ se } P\equiv Q
\end{cases}
\label{eq:rad_ac_powr_final}
\end{equation}`
Prova così.
Ciao,
ansys.