13 Novembre 2010 alle 16:32
#52281
::
`\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|}
\hline
N & $l = 83.7\mp 0.2 cm$ & $\theta$ & $T_1 (s)$ & $T_2 (s)$ & $T_3 (s)$ & $T_4 (s)$ & $T_5 (s)$ & $\bar{T}_{10} (s)$ & $\bar{T} (s)$\\
\hline
1 & & $\theta = 0.19 \; rad$ & $18.35$ & $18.47$ & $18.42$ & $18.36$ & $18.37$ & $18.39\mp 0.06$ & $1.839\mp 0.006$\\
\hline
2 & & $\theta = 0.29 \; rad$ & $18.39$ & $18.47$ & $18.42$ & $18.44$ & $18.30$ & $18.44\mp 0.05$ & $1.844\mp 0.005$\\
\hline
3 & & $\theta = 0.42 \; rad$ & $18.52$ & $18.53$ & $18.61$ & $18.59$ & $18.55$ & $18.56\mp 0.05$ & $1.856\mp 0.005$\\
\hline
\end{tabular}
`
ecco l’inquisito.