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perchè così compila:`\begin{equation}
x) \quad \rho \left(u \frac{\partial u}{\partial x} +v \frac{\partial u}{\partial y}\right)=-\frac{\partial p}{\partial x}+\frac{\partial \tau_{xx}}{\partial x} + \frac{\partial \tau_{yx}}{\partial y}
\end{equation}\begin{equation}
y) \quad \rho \left(u \frac{\partial v}{\partial x} +v \frac{\partial v}{\partial y}\right)=-\frac{\partial p}{\partial y}+\frac{\partial \tau_{xy}}{\partial x} + \frac{\partial \tau_{yy}}{\partial y}
\end{equation}`e così
`\begin{gather}
x) \quad \rho \left(u \frac{\partial u}{\partial x} +v \frac{\partial u}{\partial y}\right)=-\frac{\partial p}{\partial x}+\frac{\partial \tau_{xx}}{\partial x} + \frac{\partial \tau_{yx}}{\partial y} \\y) \quad \rho \left(u \frac{\partial v}{\partial x} +v \frac{\partial v}{\partial y}\right)=-\frac{\partial p}{\partial y}+\frac{\partial \tau_{xy}}{\partial x} + \frac{\partial \tau_{yy}}{\partial y}
\end{gather}`da
Runaway argument?
x) \quad \rho \left (u \frac {\partial u}{\partial x} +v \frac {\partial \ETC.
! Paragraph ended before \gather was complete.
\par
l.53?
Process has been terminated …
grazie
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