claudio” post=91655
non sono molto esperto ma fose la risposta è qui con matrices
Grazie per il consiglio. Non ho ben capito come utilizzare le matrici di figure. In questo modo sono obbligato a inserire le didascalie manualmente? Intendo la posizione delle didascalie.
Aggiungo un esempio “minimo”:
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\documentclass[10pt,a4paper]{article}
\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{tikz}
\usepackage{subfig}
\usepackage{siunitx}
\begin{document}
\begin{figure}
\centering
\subfloat[]
[\emph{Istante $t_0$}.]
{
\begin{tikzpicture}
\draw[thick] (0,0) — (0,3);
\draw[very thick] (0,3) to node [pos=0.5, above] {$\num{1.995}$} (-0.1995,3) — (1.969,0) to node [pos=0.5, below] {$\num{-19.69}$} (0,0);
\node at (0,-0.8) {Precompressione};
\node at (2,1.5) {$+$};
\draw[thick] (4,0) — (4,3);
\draw[very thick] (4,3) to node [pos=0.5, above] {$\num{-5.04}$} (4.504,3) — (2.98,0) to node [pos=0.5, below] {$\num{10.02}$} (4,0);
\node at (4,-0.8) {Carichi agenti};
\node at (6,1.5) {$=$};
\draw[thick] (8,0) — (8,3);
\draw[very thick] (8,3) to node [pos=0.5, above] {$\num{-3.044}$} (8.3044,3) — (8.9668,0) to node [pos=0.5, below] {$\num{-9.668}$} (8,0);
\node at (8,-0.8) {Sforzo totale};
\end{tikzpicture}
\label{fig:s.s.t0}
}\\
\subfloat[]
[\emph{Istante $t_\infty$}.]
{
\begin{tikzpicture}
\draw[thick] (0,0) — (0,3);
\draw[very thick] (0,3) to node [pos=0.5, above] {$\num{1.701}$} (-0.1701,3) — (1.69,0) to node [pos=0.5, below] {$\num{-16.9}$} (0,0);
\node at (0,-0.8) {Precompressione};
\node at (2,1.5) {$+$};
\draw[thick] (4,0) — (4,3);
\draw[very thick] (4,3) to node [pos=0.5, above] {$\num{-6.371}$} (4.6371,3) — (2.74,0) to node [pos=0.5, below] {$\num{12.67}$} (4,0);
\node at (4,-0.8) {Carichi agenti};
\node at (6,1.5) {$=$};
\draw[thick] (8,0) — (8,3);
\draw[very thick] (8,3) to node [pos=0.5, above] {$\num{-4.661}$} (8.4661,3) — (8.4233,0) to node [pos=0.5, below] {$\num{-4.233}$} (8,0);
\node at (8,-0.8) {Sforzo totale};
\end{tikzpicture}
\label{fig:s.s.tinf}
}\\
\subfloat[]
[\emph{Istante $t_1$}.]
{
\begin{tikzpicture}
\draw[thick] (0,0) — (0,3);
\draw[very thick] (0,3) to node [pos=0.5, above] {$\num{1.701}$} (-0.1701,3) — (1.69,0) to node [pos=0.5, below] {$\num{-16.9}$} (0,0);
\node at (0,-0.8) {Precompressione};
\node at (2,1.5) {$+$};
\draw[thick] (4,0) — (4,3);
\draw[very thick] (4,3) to node [pos=0.5, above] {$\num{-8.286}$} (4.8286,3) — (2.34,0) to node [pos=0.5, below] {$\num{16.65}$} (4,0);
\node at (4,-0.8) {Carichi agenti};
\node at (6,1.5) {$=$};
\draw[thick] (8,0) — (8,3);
\draw[very thick] (8,3) to node [pos=0.5, above] {$\num{-6.577}$} (8.6577,3) — (8.05,0) to node [pos=0.5, below] {$\num{-0.4239}$} (8,0);
\node at (8,-0.8) {Sforzo totale};
\end{tikzpicture}
\label{fig:s.s.t1}
}
\caption{Stato di sforzo allo Stato Limite di Esercizio (in MPa).}
\label{fig:sfor}
\end{figure}
\end{document}
`