nick87″ post=68299Ciao a tutti, prima di tutto complimenti per il forum, che molte volte mi ha supportato nelle soluzioni di certi problemi con latex 😉
Ho letto tanti post riguardo l’utilizzo di subequations, ma non ho trovato risposta al mio quesito:`
\begin{subequations}
\begin{align}\label{eq85a}
0 &= 2\dfrac{\partial \omega^1}{\partial G_{11}}+4\dfrac{\partial h'}{\partial G^2}\left(a_1G_{12}+a_2G_{22}\right)-2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}\left(a_1G_{11}+a_2G_{12}\right)-a_1\dfrac{\partial^2 h'}{\partial G_{12}} \nonumber \\
\\
0 &= 2\dfrac{\partial \omega^1}{\partial G_{12}}+2\dfrac{\partial h'}{\partial G \partial G_{12}} \left(a_1G_{12}+a_2G_{22}\right)-\dfrac{\partial^2 h'}{\partial G_{12}^2}\left(a_1G_{11}+a_2G_{12}\right)-a_2\dfrac{\partial h'}{\partial G_{12}} \nonumber
\end{align}
\\
\begin{align}\label{eq85b}
0 &= 2\dfrac{\partial \omega^2}{\partial G_{11}}+4\dfrac{\partial h'}{\partial G^2}\left(a_1G_{11}+a_2G_{12}\right)+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}\left(a_1G_{12}+a_2G_{22}\right)+2a_1\dfrac{\partial h'}{\partial G} \nonumber \\
\\
0 &= \dfrac{\partial \omega^2}{\partial G_{12}}+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}\left(a_1G_{11}+a_2G_{12}\right)+\dfrac{\partial^2 h'}{\partial G_{12}^2}\left(a_1G_{12}+a_2G_{22}\right)+2a_2\dfrac{\partial h'}{\partial G} \nonumber
\end{align}
\\
\begin{align}\label{eq85c}
0 &= \dfrac{\partial \omega^1}{\partial G_{12}}+2\dfrac{\partial^2 h'}{\partial G_{12} \partial G}\left(a_1G_{12}+a_2G_{22}\right)-\dfrac{\partial^2 h'}{\partial G_{12}^2}\left(a_1G_{11}+a_2G_{12}\right)+2a_1\dfrac{\partial h'}{\partial G} \nonumber \\
\\
0 &= 2\dfrac{\partial \omega^1}{\partial G_{22}}-4\dfrac{\partial^2 h'}{\partial G^2}\left(a_1G_{12}+a_2G_{22}\right)+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}\left(a_1G_{11}+a_2G_{12}\right)+2a_2\dfrac{\partial h'}{\partial G} \nonumber
\end{align}
\\
\begin{align}\label{eq85d}
0 &= 2\dfrac{\partial \omega^2}{\partial G_{12}}+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}(a_1G_{11}+a_2G_{12})+\dfrac{\partial^2 h'}{\partial G_{12}^2}\left(a_1G_{12}+a_2G_{22}\right)+a_1\dfrac{\partial h'}{\partial G_{12}} \nonumber \\
\\
0 &= 2\dfrac{\partial \omega^2}{\partial G_{22}}-4\dfrac{\partial^2 h'}{\partial G^2}(a_1G_{11}+a_2G_{12})-2\dfrac{\partial^2 h'}{\partial G_{12} \partial G}\left(a_1G_{12}+a_2G_{22}\right)+a_2\dfrac{\partial h'}{\partial G_{12}} \nonumber \\
\end{align}
\begin{align*}
{}
\end{align*}
\end{subequations}
`l’errore di output che noto è che mi compare il numero 85e che non è riferito a nessun’altra equazione! E mi succede anche se al posto di align uso l’ambiente eqnarray (che qualcuno dice che non si debba mai usare). Grazie… 🙂
L’idea di mettere il numero in mezzo a due righe mi pare piuttosto peregrina, così come quella di spaziare con \\:
`\begin{subequations}
\small
\begin{align}
&\begin{aligned}
0
&= 2\dfrac{\partial \omega^1}{\partial G_{11}}
+4\dfrac{\partial h'}{\partial G^2}(a_1G_{12}+a_2G_{22})
-2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}(a_1G_{11}+a_2G_{12})
-a_1\dfrac{\partial^2 h'}{\partial G_{12}}
\\
0
&= 2\dfrac{\partial \omega^1}{\partial G_{12}}
+2\dfrac{\partial h'}{\partial G \partial G_{12}} (a_1G_{12}+a_2G_{22})
-\dfrac{\partial^2 h'}{\partial G_{12}^2}(a_1G_{11}+a_2G_{12})
-a_2\dfrac{\partial h'}{\partial G_{12}}
\end{aligned}
%
\label{85e}\\[2ex]
%
&\begin{aligned}
0
&= 2\dfrac{\partial \omega^2}{\partial G_{11}}
+4\dfrac{\partial h'}{\partial G^2}(a_1G_{11}
+a_2G_{12})+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}(a_1G_{12}+a_2G_{22})
+2a_1\dfrac{\partial h'}{\partial G}
\\
0
&= \dfrac{\partial \omega^2}{\partial G_{12}}
+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}(a_1G_{11}+a_2G_{12})
+\dfrac{\partial^2 h'}{\partial G_{12}^2}(a_1G_{12}+a_2G_{22})
+2a_2\dfrac{\partial h'}{\partial G}
\end{aligned}
%
\label{eq85b}\\[2ex]
%
&\begin{aligned}
0
&= \dfrac{\partial \omega^1}{\partial G_{12}}
+2\dfrac{\partial^2 h'}{\partial G_{12} \partial G}(a_1G_{12}+a_2G_{22})
-\dfrac{\partial^2 h'}{\partial G_{12}^2}(a_1G_{11}+a_2G_{12})
+2a_1\dfrac{\partial h'}{\partial G} \\
0
&= 2\dfrac{\partial \omega^1}{\partial G_{22}}
-4\dfrac{\partial^2 h'}{\partial G^2}(a_1G_{12}+a_2G_{22})
+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}(a_1G_{11}+a_2G_{12})
+2a_2\dfrac{\partial h'}{\partial G}
\end{aligned}
%
\label{eq85c}\\[2ex]
%
&\begin{aligned}
0
&= 2\dfrac{\partial \omega^2}{\partial G_{12}}
+2\dfrac{\partial^2 h'}{\partial G \partial G_{12}}(a_1G_{11}+a_2G_{12})
+\dfrac{\partial^2 h'}{\partial G_{12}^2}(a_1G_{12}+a_2G_{22})
+a_1\dfrac{\partial h'}{\partial G_{12}} \\
0
&= 2\dfrac{\partial \omega^2}{\partial G_{22}}
-4\dfrac{\partial^2 h'}{\partial G^2}(a_1G_{11}+a_2G_{12})
-2\dfrac{\partial^2 h'}{\partial G_{12} \partial G}(a_1G_{12}+a_2G_{22})
+a_2\dfrac{\partial h'}{\partial G_{12}}
\end{aligned}
\label{85d}
\end{align}
\end{subequations}`
Se poi invece di dire \small volessi spezzare le equazioni, sarebbero già scritte a puntino.
Non usare \left e \right se non quando sono strettamente necessari.
Ciao
Enrico