Re: Mutue induttanze in CircuiTikz

#82749
Liverpool
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    Una soluzione manuale e rapida (con posizionamento ad occhio):
    `\documentclass

    {standalone}
    \usepackage{circuitikz}

    \begin{document}
    \begin{circuitikz}[american]
    \draw (0,0) to [sV] (0,3)
    to [short] (2,3);
    \ctikzset{bipoles/americaninductor/width/.initial=1.6}
    \ctikzset{bipoles/americaninductor/coils/.initial=8}
    \draw (2,3) to [L] (2,0)
    to [short] (0,0);
    \ctikzset{bipoles/americaninductor/width/.initial=0.6}
    \ctikzset{bipoles/americaninductor/coils/.initial=3}
    \draw (4,0) to [short, o-] (3,0) — (3,0.36)
    to [L] (3,1.46) -| (3.5,3) -| (3,2.79);
    \draw (4,1.69) to [short, o-] (3,1.69)
    to [L] (3,2.79);
    \node at (2.5,1.5) [shape=rectangle, draw, thick, minimum width=0.3cm, minimum height=2.6cm] {};
    \draw [latex-latex] (2.5,1) — (2.5,2);
    \end{circuitikz}
    \end{document}`

    [attachment=603]prova_2013-02-18.pdf[/attachment]

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